Differentiating tanh [Solved!]
Haida 26 Nov 2015, 08:13
My question
what the answer if we differentiate `y = tanh (x-9)`?
Relevant page
Differentiation of Transcendental Functions
What I've done so far
I tried to find this on IntMath, but couldn't.
X
what the answer if we differentiate `y = tanh (x-9)`?
Relevant page
<a href="/differentiation-transcendental/differentiate-transcendental-intro.php">Differentiation of Transcendental Functions</a>
What I've done so far
I tried to find this on IntMath, but couldn't.
Re: Differentiating tanh
Murray 26 Nov 2015, 16:36
Hello Haida
This is not "`tan`", but `"tanh`".
IntMath doesn't include the hyperbolic functions (yet), but you can see the formula for differentiating `tanh x` at:
Table of Derivatives
Your situation is a function of function situation. Do you think you can do it now?
Good luck with it.
Regards
M Bourne
X
Hello Haida
This is not "`tan`", but `"tanh`".
IntMath doesn't include the hyperbolic functions (yet), but you can see the formula for differentiating `tanh x` at:
<a href="/differentiation-transcendental/table-derivatives.php">Table of Derivatives</a>
Your situation is a function of function situation. Do you think you can do it now?
Good luck with it.
Regards
M Bourne
Re: Differentiating tanh
Haida 27 Nov 2015, 13:38
I think it's
Put `u=x-9` so `y= tanh u`.
Then `dy/dx = dy/(du) (du)/dx`
` = (1-tanh^2 u)(du)/dx = 1 - tanh^2(x-9)`.
Is it OK?
X
I think it's
Put `u=x-9` so `y= tanh u`.
Then `dy/dx = dy/(du) (du)/dx`
` = (1-tanh^2 u)(du)/dx = 1 - tanh^2(x-9)`.
Is it OK?
Re: Differentiating tanh
Murray 28 Nov 2015, 05:59
Yes, you've nailed it.
Well done.
X
Yes, you've nailed it.
Well done.
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