Discontinous functions - fourier series and taylor series [Solved!]

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can a discontinous function can be develop in fourier series and taylar series?

Relevant page

<a href="/fourier-series/2-full-range-fourier-series.php">2. Full Range Fourier Series</a>

What I've done so far

Just wondering because I tried to do a few

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Hi Gaurav

A function has to be continuous before you can expand it using Fourier or Taylors, and for Fourier the function needs to be periodic.

With Taylors though, you can limit the domain to the continuous part and then expand for that. For example, on this page:

<a href="/series-expansion/1-taylor-series.php">1. Taylor Series</a>

The example on `f(x)=log x` shows that even though it is discontinuous at `x = 0` and not defined for `x &lt; 0`, we can still do a Taylor's series expansion.

Hope that makes sense

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Yes it does. thanks