Solve e^x=x^e [Solved!]
James 18 Dec 2015, 10:21
My question
How to solve e^x=x^e?
Relevant page
Exponential & Logarithmic Functions
What I've done so far
It could not be solved by the quadratic equation.
James 18 Dec 2015, 10:21
How to solve e^x=x^e?
Exponential & Logarithmic Functions
It could not be solved by the quadratic equation.
X
How to solve e^x=x^e?
Relevant page <a href="/exponential-logarithmic-functions/exponential-log-functions-intro.php">Exponential & Logarithmic Functions</a> What I've done so far It could not be solved by the quadratic equation.
Murray 18 Dec 2015, 21:26
Hi James
Well, your problem cannot be solved using quadratic equations (because it isn't a quadratic equation). Actually, it can't be solved using ordinary algebra at all.
My first thought was to take log of both sides, but that doesn't give us anything we can solve:
`"LHS" = ln e^x = x ln e = x`
`"RHS" = e ln x`
So I would suggest using graphs, like I do on this page:
5. Graphical Solution of non-linear Systems
Your "system" is actually
`y = e^x`
`y = x^e`
Another way to do it would be to graph
`y = e^x - x^e` and see where it intersects the x axis.
Hope that helps.
X
Hi James Well, your problem cannot be solved using quadratic equations (because it isn't a quadratic equation). Actually, it can't be solved using ordinary algebra at all. My first thought was to take log of both sides, but that doesn't give us anything we can solve: `"LHS" = ln e^x = x ln e = x` `"RHS" = e ln x` So I would suggest using graphs, like I do on this page: <a href="/systems-of-equations/5-graphical-solution-non-linear-system.php">5. Graphical Solution of non-linear Systems</a> Your "system" is actually `y = e^x` `y = x^e` Another way to do it would be to graph `y = e^x - x^e` and see where it intersects the x axis. Hope that helps.
James 19 Dec 2015, 11:15
ok, I'll try the graph thing here.
First method (graphing `y=e^x` and `y=x^e` on the same axes):
It's not easy to see the solution there.
Second method (graphing `y=e^x - x^e`:
It looks like the answer is around `x=2.7`
Checking: `e^2.7 ~~ 14.8797`
`2.7^e = 14.8788`
Close enough!
Thanks a lot.
X
ok, I'll try the graph thing here. First method (graphing `y=e^x` and `y=x^e` on the same axes): [graph]310,250;-1,4;-1,30,1,5;e^x,x^e[/graph] It's not easy to see the solution there. Second method (graphing `y=e^x - x^e`: [graph]310,250;1,3;-0.5,2,0.1,0.1;e^x-x^e[/graph] It looks like the answer is around `x=2.7` Checking: `e^2.7 ~~ 14.8797` `2.7^e = 14.8788` Close enough! Thanks a lot.
X
Well done, James! You're very welcome.
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